28x^2-19xy+3y^2=

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Solution for 28x^2-19xy+3y^2= equation: 


Simplifying
28x2 + -19xy + 3y2 = 0

Reorder the terms:
-19xy + 28x2 + 3y2 = 0

Solving
-19xy + 28x2 + 3y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(7x + -3y)(4x + -1y) = 0


Subproblem 1
Set the factor '(7x + -3y)' equal to zero and attempt to solve:

Simplifying
7x + -3y = 0

Solving
7x + -3y = 0

Move all terms containing x to the left, all other terms to the right.

Add '3y' to each side of the equation.
7x + -3y + 3y = 0 + 3y

Combine like terms: -3y + 3y = 0
7x + 0 = 0 + 3y
7x = 0 + 3y
Remove the zero:
7x = 3y

Divide each side by '7'.
x = 0.4285714286y

Simplifying
x = 0.4285714286y

Subproblem 2
Set the factor '(4x + -1y)' equal to zero and attempt to solve:

Simplifying
4x + -1y = 0

Solving
4x + -1y = 0

Move all terms containing x to the left, all other terms to the right.

Add 'y' to each side of the equation.
4x + -1y + y = 0 + y

Combine like terms: -1y + y = 0
4x + 0 = 0 + y
4x = 0 + y
Remove the zero:
4x = y

Divide each side by '4'.
x = 0.25y

Simplifying
x = 0.25y
Solution
x = {0.4285714286y, 0.25y}

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